2510 CHAPTER 74. A MORE ATTRACTIVE VERSION

74.4 A Simplification Of The FormulaThis estimate in Lemma 74.3.2 also provides a way to simplify one of the formulas derivedearlier in the case that X0 ∈ Lp (Ω,V ) so that X−X0 ∈ Lp ([0,T ]×Ω,V ). Refer to 74.3.11.One term there is

⟨B(X (t1)−X0−M (t1)) ,X (t1)−X0−M (t1)⟩

Also,⟨B(X (t1)−X0−M (t1)) ,X (t1)−X0−M (t1)⟩

≤ 2⟨B(X (t1)−X0) ,X (t1)−X0⟩+2⟨BM (t1) ,M (t1)⟩It was observed above that 2⟨BM (t1) ,M (t1)⟩ → 0 a.e. and also in L1 (Ω) as k→∞. Applythe above lemma to ⟨B(X (t1)−X0) ,X (t1)−X0⟩ using [0, t1] instead of [0,T ] . The new X0equals 0. Then from the estimate 74.3.8, it follows that

E (⟨B(X (t1)−X0) ,X (t1)−X0⟩)→ 0

as k→ ∞. Taking a subsequence, we could also assume that

⟨B(X (t1)−X0) ,X (t1)−X0⟩ → 0

a.e. ω as k→ ∞. Then, using this subsequence, it would follow from 74.3.11,

⟨BX (tm) ,X (tm)⟩−⟨BX0,X0⟩= e(k)+

2∫ tm

0⟨Y (u) ,X r

k (u)⟩du++2∫ tm

0

⟨BX l

k ,dM⟩

+m−1

∑j=0

⟨B(M(t j+1

)−M (t j)

),M(t j+1

)−M (t j)

⟩−

m−1

∑j=1

⟨B(∆X (t j)−∆M (t j)) ,∆X (t j)−∆M (t j)

⟩(74.4.17)

where e(k)→ 0 in L1 (Ω) and a.e. ω and

∆X (t j)≡ X(t j+1

)−X (t j)

∆M (t j) being defined similarly. Note how this eliminated the need to consider the term

⟨B(X (t1)−X0−M (t1)) ,X (t1)−X0−M (t1)⟩

in passing to a limit. This is a very desirable thing to be able to conclude.Can you obtain something similar even in case X0 is not assumed to be in Lp (Ω,V )?

Let X0k ∈ Lp (Ω,V )∩L2 (Ω,W ) ,X0k → X0 in L2 (Ω,W ) . Then from the usual argumentsinvolving the Cauchy Schwarz inequality,

⟨B(X (t1)−X0) ,X (t1)−X0⟩1/2 ≤ ⟨B(X (t1)−X0k) ,X (t1)−X0k⟩1/2

+⟨B(X0k−X0) ,X0k−X0⟩1/2

2510 CHAPTER 74. A MORE ATTRACTIVE VERSION74.4 A Simplification Of The FormulaThis estimate in Lemma 74.3.2 also provides a way to simplify one of the formulas derivedearlier in the case that Xo € L? (Q,V) so that X — Xo € L? ([0,T] x Q,V). Refer to 74.3.11.One term there is(B(X (41) —Xo0 —M (1) X (41) —X0 —M (t1))Also,(B(X (t1) —Xo —M (t1)) ,X (t1) —X0 —M (n))<2(B(X (1) — Xo) ,X (t1) — Xo) +2 (BM (t1) ,M (t1))It was observed above that 2 (BM (t,) ,M (t,)) + 0 a.e. and also in L' (Q) as k > 09. Applythe above lemma to (B(X (t) — Xo) ,X (t1) — Xo) using [0,1] instead of [0,7]. The new Xoequals 0. Then from the estimate 74.3.8, it follows thatE ((B(X (t1) — Xo) ,X (t1) —X0)) 3 0as k — oo, Taking a subsequence, we could also assume that(B(X (t1) — Xo) ,X (1) —X0) 40a.e. @ as k — oo. Then, using this subsequence, it would follow from 74.3.11,(BX (tm) ,X (tm)) — (BXo0, Xo) = e(k) +2["w XE (w)du++2 [" (BXj,dM)Ye (M (tj41) —M (t;)) M (tj41) —M (t;))-y (B(AX (tj) — AM (t;)) ,AX (t;) — AM (t;)) (74.4.17)where e (k) + 0 in L! (Q) and a.e. @ andAX (t;) =X (ti41) — X (t;)AM (t;) being defined similarly. Note how this eliminated the need to consider the term(B(X (1) —Xo —M (11) ,X (1) —X0 —M (t1))in passing to a limit. This is a very desirable thing to be able to conclude.Can you obtain something similar even in case Xo is not assumed to be in L? (Q,V)?Let Xox € L? (Q,V) NL? (Q,W) ,Xox — Xo in L?(Q,W). Then from the usual argumentsinvolving the Cauchy Schwarz inequality,(B(X (t1) —Xo),X (t1)— Xo)? << (B(X (t1) — Xox) ,X (1) — Xo)”+ (B(Xox —Xo) .Xo« — Xo)”