2478 CHAPTER 73. THE HARD ITO FORMULA, IMPLICIT CASE

From 73.4.16,

supt /∈Nω

⟨BX (t) ,X (t)⟩=C (ω) a.e.ω

where∫

ΩC (ω)dP < ∞. In particular, supt /∈Nω

⟨BX (t) ,X (t)⟩ is bounded for a.e. ω say forω /∈N where N includes the earlier sets of measure zero. This shows that BX (t) is boundedin W ′ for t ∈ NC

ω .If v ∈V, then for ω /∈ N,

limt→s⟨BX (t) ,v⟩= ⟨BX (s) ,v⟩ , t,s

Therefore, since for such ω, ∥BX (t)∥W ′ is bounded for t /∈ Nω , the above holds for allv ∈W also. Therefore, for a.e. ω, t → BX (t,ω) is weakly continuous with values in W ′

for t /∈ Nω .Note also that

∥BX∥2W ′ ≡

(sup∥y∥W≤1

⟨BX ,y⟩)2

≤ sup∥y∥≤1

(⟨BX ,X⟩1/2 ⟨By,y⟩1/2

)2

≤ ⟨BX ,X⟩∥B∥

and so ∫ T

0

∫Ω

∥BX (t)∥2 dPdt ≤∫

∫ T

0∥B∥⟨BX (t) ,X (t)⟩dtdP

≤C(||Y ||K′ , ||X ||K , ||Z||J ,∥⟨BX0,X0⟩∥L1(Ω)

)∥B∥T (73.4.17)

Eventually, it is shown that in fact, the function t→ BX (t,ω) is continuous with valuesin W ′. The above shows that BX ∈ L2 ([0,T ]×Ω,W ′).

Finally consider the claim of weak continuity of BX into W ′. From the integral equa-tion, BX is continuous into V ′. Also BX is bounded on NC

ω . Let s ∈ [0,T ] be arbitrary. Iclaim that if tn→ s, tn ∈D, it follows that BX (tn)→ BX (s) weakly in W ′. If not, then thereis a subsequence, still denoted as tn such that BX (tn)→ Y weakly in W ′ but Y ̸= BX (s) .However, the continuity into V ′ means that for all v ∈V,

⟨Y,v⟩= limn→∞⟨BX (tn) ,v⟩= ⟨BX (s) ,v⟩

which is a contradiction since V is dense in W . This establishes the claim. Also this showsthat BX (s) is bounded in W ′.

|⟨BX (s) ,w⟩|= limn→∞|⟨BX (tn) ,w⟩| ≤ lim inf

n→∞∥BX (tn)∥W ′ ∥w∥W ≤C (ω)∥w∥W

Now a repeat of the above argument shows that s→ BX (s) is weakly continuous into W ′.

2478 CHAPTER 73. THE HARD ITO FORMULA, IMPLICIT CASEFrom 73.4.16,sup (BX (t) ,X (t)) =C(@) ae.@t¢éNowhere fg C(@)dP <e. In particular, sup,¢y,, (BX (t) ,X (t)) is bounded for a.e. @ say foro ¢ N where N includes the earlier sets of measure zero. This shows that BX (t) is boundedin W’ fort € NS.If v € V, then for @ ZN,lim (BX (t),v) = (BX (s),v), t,87sTherefore, since for such @, ||BX (t)||y, is bounded for tf ¢ Nw, the above holds for allv € W also. Therefore, for a.e. @, t > BX (t,@) is weakly continuous with values in W’fort ¢ No.Note also that22|BX |v = (se 1x0) < sup ((BX,X)!/? (By,y)'7)llylw<! IlyI|<1< (BX,X) |Band soT 2 T[ [exo apa< | | \|Bl| (BX (t) ,.X (0) dtdPSC (\I¥ hx IX lla slIZlly > I(BX0.o)lle1(ay) BIT (73.4.17)Eventually, it is shown that in fact, the function t + BX (t, @) is continuous with valuesin W’. The above shows that BX € L? ([0,7] x Q,W’).Finally consider the claim of weak continuity of BX into W’. From the integral equa-tion, BX is continuous into V’. Also BX is bounded on NS. Let s € [0,7] be arbitrary. Iclaim that if t, > s,f, € D, it follows that BX (t,) + BX (s) weakly in W’. If not, then thereis a subsequence, still denoted as ¢, such that BX (t,) + Y weakly in W’ but Y 4 BX (s).However, the continuity into V’ means that for all v € V,(Y,v) = lim (BX (t,) ,v) = (BX (s) ,v)noowhich is a contradiction since V is dense in W. This establishes the claim. Also this showsthat BX (s) is bounded in W’.| (BX (s) ,w)| = lim | (BX (th) ,w)| < lim inf ||BX (tn) Ihwr lvl <C(@) [helln-ooNow a repeat of the above argument shows that s +> BX (s) is weakly continuous into W’.