11.2. THE AREA MEASURE ON A MANIFOLD 267

By Lemma 10.4.1, the assumptions of differentiability imply that the boundary points ofΩ are always mapped to a set of measure zero so these can be neglected if desired. NowS j (Vj ∩Ui) = S j ◦R−1

i (Ri (Vj ∩Ui)) and so using 11.6, the above expression equalsr

∑i=1

∫Ri(V j∩Ui)

f(R−1

i (u))

ψ i(R−1

i (u))

η j(R−1

i (u))·∣∣∣det

(D(Ri ◦S−1

j

)(v))∣∣∣Ji (u)

∣∣detD(S j ◦R−1

i)(u)∣∣du

Now I =(Ri ◦S−1

j

)◦(S j ◦R−1

i

)and so the chain rule implies that the product of the two

Jacobians is 1. Hence 11.7 equalss

∑j=1

r

∑i=1

∫Ri(V j∩Ui)

f(R−1

i (u))

ψ i(R−1

i (u))

η j(R−1

i (u))

Ji (u)du

=r

∑i=1

s

∑j=1

∫Ri(Ui)

f(R−1

i (u))

ψ i(R−1

i (u))

η j(R−1

i (u))

Ji (u)du

=r

∑i=1

∫Ri(Ui)

f(R−1

i (u))

ψ i(R−1

i (u)) s

∑j=1

η j(R−1

i (u))

Ji (u)du

=r

∑i=1

∫Ri(Ui)

f(R−1

i (u))

ψ i(R−1

i (u))

Ji (u)du = L( f )

Thus L is a well defined positive linear functional. ■

Definition 11.2.3 By the representation theorem for positive linear functionals,Theorem 8.8.2, there exists a complete Radon measure σ p defined on the Borel sets ofΩ such that L f =

∫Ω

f dσ p. Then σ p is what is meant by the measure on the differentiablemanifold Ω.

If O is an open set in Ω, what is σ p (O)? Let fn ↑XO where fn is continuous. Then bythe monotone convergence theorem,

σ p (O) = limn→∞

L( fn) = limn→∞

r

∑i=1

∫Ri(Ui)

fn(R−1

i (u))

ψ i(R−1

i (u))

Ji (u)du

= limn→∞

r

∑i=1

∫Ri(Ui∩O)

fn(R−1

i (u))

ψ i(R−1

i (u))

Ji (u)du

=r

∑i=1

∫Ri(Ui∩O)

XO(R−1

i (u))

ψ i(R−1

i (u))

Ji (u)du.

If K is a compact subset of some Ui, then use Corollary 10.8.5 to obtain a partition ofunity which has ψ i = 1 on K so that all other ψ j equal 0. Then∫

XKdσ p =∫Ri(Ui)

XK(R−1

i (u))

Ji (u)du

It then follows from regularity of the measure and the monotone convergence theorem thatif E is any measurable set contained in Ui, you can replace K in the above with E. Ingeneral, this implies that for nonnegative measurable f , having support in Ui,∫

f dσ p =∫Ri(Ui)

f(R−1

i (u))

Ji (u)du

11.2. THE AREA MEASURE ON A MANIFOLD 267By Lemma 10.4.1, the assumptions of differentiability imply that the boundary points ofQ are always mapped to a set of measure zero so these can be neglected if desired. NowSj (V;NU;) = $j; 0 R; | (R;(V;NU;)) and so using 11.6, the above expression equalsY Ira wy (u)) wi (Re (uw) nj (Re! (u))-det (p (Rios;') (v)) li (uw) |detD (Sjo.R;') (u)|duNow /= (R, oS 7') ° (S jo R, ') and so the chain rule implies that the product of the twoJacobians is 1. Hence 11.7 equalsf (R;! (w)) y, (Re! (w)) 1; (Rj! (w)) Jj (w) duMrorallunlluni(VjNU;)> =o=IMM:Me.ll~.ilaif (R; | (uw) w;(R; | (uw) 1; (BR; (u)) Ji(ee) duIM-Faswy! (u)) vi (Bi ( w) Leni u)) Ji(u)du_~ il~ Y boca Bi (u)) w; (R; | (w)) J; (u) du =L(f)i=!Thus L is a well defined positive linear functional. HHDefinition 11.2.3 By the representation theorem for positive linear functionals,Theorem 8.8.2, there exists a complete Radon measure Oy defined on the Borel sets ofQ such that Lf = Ja fdop. Then Op is what is meant by the measure on the differentiablemanifold Q.If O is an open set in Q, what is 0, (O)? Let f, + 2o where f, is continuous. Then bythe monotone convergence theorem,5)(0) = lim L(fn) = lim Y hen! (u)) w; (Rj! (w)) J; (w) dunoo= im > |, vino tt (Bi (4) wi (R5! (w)) Jil) dun—s00- y Loco Xo (Rj! (u)) w; (Ry " (w)) Ji (u) du,If K is a compact subset of some Uj, then use Corollary 10.8.5 to obtain a partition ofunity which has y; = | on K so that all other y; equal 0. ThenL Xedop = [. ay TERE Cw) HwaIt then follows from regularity of the measure and the monotone convergence theorem thatif E is any measurable set contained in U;, you can replace K in the above with E. Ingeneral, this implies that for nonnegative measurable f, having support in Uj,[ fae ~ I. uy Br (w)) Jj (w) dui\Y7