79.4. STOCHASTIC INCLUSIONS WITHOUT UNIQUENESS ?? 2715

and solim sup

n→∞

⟨zn,un⟩V ′,V ≤ ⟨z,u⟩V ′,V

Now it follows that

lim supn→∞

⟨zn,un−u⟩V ′,V ≤ ⟨z,u⟩V ′,V −⟨z,u⟩V ′,V = 0 (79.4.56)

Thus in the situation of 79.4.44, we get 79.4.56. We state this as the following lemma.

Lemma 79.4.8 Suppose un,zn are progressively measurable, zn ∈ Â(un) , and

un (t)−u0 +1n

∫ t

0Funds+

∫ t

0znds =

∫ t

0f ds+

∫ t

0ΦdW

Then there is a subsequence, still denoted with n such that 79.4.56 holds.

Now the following is the main limit lemma which is a statement about this subsequencesatisfying 79.4.56. This lemma gives a useable limit condition for the Nemytskii operators.

Lemma 79.4.9 Suppose conditions 1 - 79.4.2 hold. Also, suppose U is a separable Banachspace dense in V, a reflexive separable Banach space and V is dense in a Hilbert space Hidentified with its dual space. Thus

U ⊆V ⊆ H = H ′ ⊆V ′ ⊆U ′,

Hypotheses: For f ∈ V ′

un (t)−u0 +1n

∫ t

0Funds+

∫ t

0znds =

∫ t

0f ds+

∫ t

0ΦdW in U ′ (**)

un and zn are P measurable

un→ u weakly in V , zn→ z weakly in U ′

lim supn→∞

⟨zn,un−u⟩V ′,V ≤ 0, (*)

Note that from the above discussion, * follows ** from taking a suitable subsequence.Assume also that for some set of measure zero N, if ω /∈ N,

supt∈[0,T ]

λ |un (t,ω)|2H ≤C (ω) , C (·) ∈ L1 (Ω) (79.4.57)

(Since we are assuming that λ = 0 in 3, this condition is automatic, but if you did have79.4.57 for λ > 0, then the following argument will show how to use it.)

Conclusion: If the above conditions hold, then there exists a further subsequence, stilldenoted with n such that for any v ∈ V , there exists z(v) ∈ Â(u) with

lim infn→∞⟨zn,un− v⟩V ′,V ≥ ⟨z(v) ,u− v⟩V ′,V .

Also z ∈ Â(u) and u,z are progressively measurable and

u(t)−u0 +∫ t

0zds =

∫ t

0f ds+

∫ t

0ΦdW in V ′

for all ω off a set of measure zero.

79.4. STOCHASTIC INCLUSIONS WITHOUT UNIQUENESS ?? 2715and solim sup (Zn Un) yy < (Z,U) yryn—ooNow it follows thatlim sup (Zn Un _ Udy y < (Z,U)yry _ (Z,U)yry =0 (79.4.56)n—-pooThus in the situation of 79.4.44, we get 79.4.56. We state this as the following lemma.Lemma 79.4.8 Suppose un,Zn are progressively measurable, z, € A (un), and1 st t t tUn (t) -w+- [ Funds+ | Zy,ds = i fas+ | @Odwn JO 0 JO 0Then there is a subsequence, still denoted with n such that 79.4.56 holds.Now the following is the main limit lemma which is a statement about this subsequencesatisfying 79.4.56. This lemma gives a useable limit condition for the Nemytskii operators.Lemma 79.4.9 Suppose conditions 1 - 79.4.2 hold. Also, suppose U is a separable Banachspace dense in V, a reflexive separable Banach space and V is dense in a Hilbert space Hidentified with its dual space. ThusUCVCH=H'CV'CU,,Hypotheses: For f € ¥'1 t t t tn(t)—uy+— | Funds+ [ ands= | fas+ | ®dW in U’ (**)nJo 0 0 0Un and Zp are Y measurableUn — u weakly in V, z, — z weakly in ZY’lim sup (Zn, Un —U) yr y <0, (*)nooNote that from the above discussion, * follows ** from taking a suitable subsequence.Assume also that for some set of measure zero N, if o ¢ N,sup A |un(t,@)|z, <C(@), C(-) € L'(Q) (79.4.57)te(0,T](Since we are assuming that 1 = 0 in 3, this condition is automatic, but if you did have79.4.57 for A > 0, then the following argument will show how to use it.)Conclusion: If the above conditions hold, then there exists a further subsequence, stilldenoted with n such that for any v € Y, there exists z(v) € A(u) withlim inf (Zn, Un ~~ Vyy 2 (z (v) U— Vd yy .Also z€ A (u) and u,z are progressively measurable andot t tu(t) —w+ | zds =| fas+ | @dW in V'0 0 0for all @ off a set of measure zero.