78.2. MEASURABLE SOLUTIONS TO EVOLUTION INCLUSIONS 2667

Then act on J−1Luε on both sides in the above. This yields for some C dependent on B′ aninequality of the following form.

−εC ||Luε ||2 + ||Luε ||2 +⟨w∗ε ,J

−1Luε

⟩≤⟨

f ,J−1Luε

⟩(78.2.16)

Also, acting on both sides of 78.2.14 with uε and using the formula for ⟨Ku,u⟩ ,

ε⟨Luε ,J−1Luε

⟩+

12[⟨Buε ,uε⟩(T )+ ⟨Buε ,uε⟩(0)]

+12

∫ T

0⟨B′ (t)uε (t) ,uε (t)⟩dt + ⟨w∗ε ,uε⟩V ′,V = ⟨ f ,uε⟩+ ⟨Buε (0) ,u0 (ω)⟩

= ⟨ f ,uε⟩+ ⟨Bu0 (ω) ,u0 (ω)⟩

It follows easily from the coercivity condition 78.1.6 that uε is bounded in V and conse-quently w∗ε is bounded in V ′, this from the growth estimate 78.1.1. Now from 78.2.16, italso follows that ||Luε ||V ′ is bounded for small ε . Thus

||Luε (ω)||V ′ + ||uε (ω)||V + ||w∗ε (ω)||V ′ ≤C (ω)< ∞,

C (ω) independent of small ε . By Theorem 78.1.3, there is a subsequence ε (ω)→ 0 suchthat (

Luε(ω) (ω) ,uε(ω) (ω) ,w∗ε(ω) (ω) ,Buε(ω) (ω)(0)

)→

(Lu(ω) ,u(ω) ,ξ (ω) ,Bu(ω)(0)) (78.2.17)

in V ′×V ×V ′×V ′ weakly and ω→ (Lu(ω) ,u(ω) ,ξ (ω)) is measurable into V ′×V ×V ′. It follows that Bu(ω)(0) = Bu0 (ω) because each Buε(ω) (ω)(0) = Bu0 (ω). Note thatthis also shows that Kuε ⇀ Ku in X ′. Thus, suppressing the dependence on ω, use 78.2.14to act on uε −u and obtain

ε⟨Luε −Lu,J−1Luε

⟩+ ⟨Kuε ,uε −u⟩+ ⟨w∗ε ,uε −u⟩= ⟨ f ,uε −u⟩+ ⟨g,uε −u⟩

Using monotonicity of J−1,

ε⟨Luε −Lu,J−1Lu

⟩+ ⟨Kuε ,uε −u⟩+ ⟨w∗ε ,uε −u⟩ ≤ ⟨ f ,uε −u⟩+ ⟨g,uε −u⟩

Now (Buε −Bu)(0) = 0. Therefore, uε −u ∈ D(Λ) and so

ε⟨Λ∗J−1Lu,uε −u

⟩+ ⟨Kuε ,uε −u⟩+ ⟨w∗ε ,uε −u⟩ ≤ ⟨ f ,uε −u⟩+ ⟨g,uε −u⟩

Recall that K is monotone, bounded and hemicontinuous. In fact, it is monotone and linear.Hence, K +A is pseudomonotone. Then from the above,

lim supε→0⟨Kuε +w∗ε ,uε −u⟩ ≤ 0

Now these weak convergences in 78.2.17 include the weak convergence of uε to u in X .Thus, since K +A(·,ω) is pseudomonotone as a map from X to P (X ′) , for every v ∈ X ,there exists w∗ (v) ∈ K (u)+A(u,ω) such that

lim infε→0⟨Kuε +w∗ε ,uε − v⟩ ≥ ⟨w∗ (v) ,u− v⟩

78.2. MEASURABLE SOLUTIONS TO EVOLUTION INCLUSIONS 2667Then act on J~!Lug on both sides in the above. This yields for some C dependent on B’ aninequality of the following form.~€C ||Lue||” +||Luel|? + (wi, J Lue) < (f,J~'Lue) (78.2.16)Also, acting on both sides of 78.2.14 with we and using the formula for (Ku, u) ,€ (Lite,J~" Lite) + 5 ((Bue, ue) (T) + (Bue, ue) (0)]+5 [Bl Cue) ue (ae + wes) yey = (f,ue) + (Bug (0) ,uo (@))= (f,We) + (Bug (@) ,uo (@))It follows easily from the coercivity condition 78.1.6 that ug is bounded in Y and conse-quently w; is bounded in ¥’, this from the growth estimate 78.1.1. Now from 78.2.16, italso follows that ||Lue||7 is bounded for small €. ThusI[Lue (®)|| yr + ||ue (@)ly + Ilwe (@)|ly1 SC(@) <,C(@) independent of small €. By Theorem 78.1.3, there is a subsequence €(@) — 0 suchthat(Lecco) (@) ,Ue(e) (®) Weve )(@ ); Bue(o @) (0 ))>)((Lu(@) ,u(@), (@) ,Bu(@) (0)) (78.2.17))o)inV’x¥ x V'xV!' weakly and @ — (Lu(@) ,u(@) ,& (@)) is measurable into W' x V x¥'. It follows that Bu (@) (0) = Buo (@) because each Bug(m) (@) (0) = Bug (@). Note thatthis also shows that Kug — Ku in X'. Thus, suppressing the dependence on @, use 78.2.14to act on ug — u and obtain€ (Lute — Lu, J~' Lue) + (Kite, We — U) + (We, Ue — ul) = (f ug —Uu) + (9, Ue —U)Using monotonicity of J~!,€ (Lue — Lu, J~' Lu) + (Kue, Ue — u) + (we, Ue —u) < (fe —u) + (8, Ue — U)Now (Bug — Bu) (0) = 0. Therefore, ug — u € D(A) and so€(A*J~!Lu,ue —u) + (Kile, We — U) + (We, Ue —U) < (fy ue —u) + (g,Ue —U)Recall that K is monotone, bounded and hemicontinuous. In fact, it is monotone and linear.Hence, K +A is pseudomonotone. Then from the above,lim sup (Kug +We,Ue —Uu) <0€é0Now these weak convergences in 78.2.17 include the weak convergence of ug to u in X.Thus, since K + A(-,@) is pseudomonotone as a map from X to A(X’), for every vE X,there exists w* (v) € K (u) +A (u,@) such thatlim inf (Kug + Wz, Ue —v) > (w* (v) ,u—v)€é0