77.2. SOME FUNDAMENTAL THEOREMS 2601

Proof: From the definition of Γ(ω) = ∩∞n=1Γn (ω) it follows that ω → Γ(ω) is a com-

pact set-valued map in X and is nonempty because each Γn (ω) is nonempty and compact,and the Γn (ω) are nested. We next show that ω → Γ(ω) is F measurable. Indeed, eachΓn is compact valued and F measurable so, if F is closed,

Γ(ω)∩F = ∩∞n=1Γ

n (ω)∩F,

and the left-hand side is not empty if and only if each Γn (ω)∩F ̸= /0. Thus, for F closed,

{ω : Γ(ω)∩F ̸= /0}= ∩n {ω : Γn (ω)∩F ̸= /0} ,

and soΓ− (F) = ∩nΓ

n− (F) ∈F .

The last claim follows from the theory of multi-functions, see, e.g., [10, 70] or Section 48.See Proposition 48.1.4. The fact that Γn (ω) is compact, Γn is measurable and Γn− (U) ∈F , for U open, imply the strong measurability of Γn [10, 70] see also Section 48, andalso that Γn− (F) ∈ F . Thus, ω → Γ(ω) is a nonempty compact valued in X and Fmeasurable. We are using the theorem which says that when Γ has compact values, thenone can conclude that strong measurability and measurability coincide. This is why we cansay that Γn− (F) ∈F .

The standard theory [10, 70], Section 48, also guarantees the existence of an F mea-surable selection ω → γ (ω) with γ (ω) ∈ Γ(ω), for each ω , and also that t → γk (t,ω)(the kth component of γ) is continuous. Next, we consider the product measurability of γk.We know that ω → γk (ω) is F measurable into C ([0,T ]) and since pointwise evaluationis continuous, ω → γk (t,ω) is F measurable. (This is nothing more than a case of thegeneral result that a continuous function of a measurable function is measurable.) Then,since t→ γk (t,ω) is continuous, it follows that γk is a P measurable real valued functionand that γ is a P measurable R∞ valued function. Since γ (ω) ∈ Γ(ω) , it follows that foreach n,γ (ω) ∈ Γn (ω) . Therefore, there exists jn ≥ n such that for each ω ,

d (f(XNC (ω)u jn (·,ω)) ,γ (ω))< 2−n.

Therefore, for a suitable subsequence{

un(ω) (·,ω)}

, we have

γ (ω) = limn(ω)→∞

f(XNC (ω)un(ω) (·,ω)

),

for each ω . In particular, for each k

γk (t,ω) = limn(ω)→∞

f(XNC (ω)un(ω) (t,ω)

)k

= limn(ω)→∞

mk

∫ t

lmk (t)

⟨φ rk

,XNC (ω)un(ω) (s,ω)⟩

Vds, (77.2.3)

for each t.Note that it is not clear that (t,ω)→ f

(XNC (ω)un(ω) (t,ω)

)is P measurable, al-

though (t,ω)→ γ (t,ω) is P measurable.

77.2. SOME FUNDAMENTAL THEOREMS 2601Proof: From the definition of [(@) = N°_,I" (@) it follows that @ + I'(@) is a com-pact set-valued map in X and is nonempty because each I” (@) is nonempty and compact,and the I” (@) are nested. We next show that @ > I'(@) is ¥ measurable. Indeed, eachI” is compact valued and .Y measurable so, if F is closed,T(@)AF =n I" (@) NF,and the left-hand side is not empty if and only if each I" (@) NF 40. Thus, for F closed,{o:T(@)nF 40} =n, {o:I"(@)nF £90},and soI” (F)=n,I" (F) € F.The last claim follows from the theory of multi-functions, see, e.g., [10, 70] or Section 48.See Proposition 48.1.4. The fact that I” (@) is compact, I” is measurable and I~ (U) €F, for U open, imply the strong measurability of T” [10, 70] see also Section 48, andalso that [”" (F) € #. Thus, @ + T(@) is a nonempty compact valued in X and Fmeasurable. We are using the theorem which says that when I’ has compact values, thenone can conclude that strong measurability and measurability coincide. This is why we cansay that” (F) € F.The standard theory [10, 70], Section 48, also guarantees the existence of an ¥ mea-surable selection @ + y(@) with y(@) € T'(@), for each @, and also that t > y, (t,@)(the k” component of 7) is continuous. Next, we consider the product measurability of Y,.We know that @ > y,(@) is ¥ measurable into C ([0,7]) and since pointwise evaluationis continuous, @ > ¥;, (t,@) is measurable. (This is nothing more than a case of thegeneral result that a continuous function of a measurable function is measurable.) Then,since t + Y; (t,@) is continuous, it follows that y, is a Y measurable real valued functionand that y is a Y measurable R® valued function. Since y(@) € '(@), it follows that foreach n, y(@) € I” (@). Therefore, there exists j, > such that for each a,d(£( 2c (@) uj, (-,@)),Y(@)) <2",Therefore, for a suitable subsequence {Un(o) (-,@) }, we havey(@) = lim £( Lye (@) Uni) (-.@)),n(@)—e0for each a. In particular, for each k%(t,@) = lim £(2%yc (@) un(e) (1,)),n(@)—e0t= lim (G1: Ze (@) tno) (8,0) ds, 77.2.3lita im, (ns Pie (tno (5.0), as (77.2.3)foreacht.Note that it is not clear that (t,@) + f(2yc (@) un(@) (t,@)) is A measurable, al-though (t,@) > y(t,@) is Y measurable.