77.2. SOME FUNDAMENTAL THEOREMS 2599

For fixed ω /∈ N and k, the functions{

t→ fk (u j (·,ω))(t)}

j are uniformly boundedand equicontinuous because they are in C0,1 ([0,T ]). Indeed, we have for ω /∈ N,

∣∣ fk (u j (·,ω))(t)∣∣= ∣∣∣∣∣mk

∫ t

lmk (t)

⟨φ rk

,u j (s,ω)⟩

Vds

∣∣∣∣∣≤C (ω)∥∥∥φ rk

∥∥∥V

and for t ≤ t ′ ∣∣ fk (u j (·,ω))(t)− fk (u j (·,ω))(t ′)∣∣

∣∣∣∣∣mk

∫ t

lmk (t)

⟨φ rk

,u j (s,ω)⟩

Vds−mk

∫ t ′

lmk (t′)

⟨φ rk

,u j (s,ω)⟩

Vds

∣∣∣∣∣≤ 2mk

∣∣t ′− t∣∣C (ω)

∥∥∥φ rk

∥∥∥V ′.

By Lemma 77.2.5, the set of functions{XNC (ω) f(u j (·,ω))

}∞

j=n is pre-compact in X =

∏k C ([0,T ]) . We now define a set valued map Γn : Ω→ X by

Γn (ω)≡ ∪ j≥n

{XNC (ω) f(u j (·,ω))

},

where the closure is taken in X . Then Γn (ω) is the closure of a pre-compact set in X andso Γn (ω) is compact in X . From the definition, a function f is in Γn (ω) if and only ifd (f,XNC (ω) f(wl))→ 0 as l→ ∞, where each wl is one of the u j (·,ω) for j ≥ n. In thetopology on X , this happens iff for every k,

fk (t) = liml→∞

mk

∫ t

lmk (t)

⟨φ rk

,XNC (ω)wl (s,ω)⟩

Vds,

where the limit is the uniform limit in t.

Lemma 77.2.6 The mapping ω→ Γn (ω) is an F measurable set-valued map with valuesin X. If σ is a measurable selection, then for each t, ω → σ (t,ω) is F measurable and(t,ω)→ σ (t,ω) is B ([0,T ])×F measurable.

We note that if σ is a measurable selection then σ (ω) ∈ Γn (ω), so σ = σ (·,ω) is acontinuous function. To have σ measurable would mean that σ

−1k (open) ∈F , where the

open set is in C ([0,T ]).Proof: Let O be a basic open set in X . Then O = ∏

∞k=1 Ok, where Ok is a proper open

set of C ([0,T ]) only for k ∈ {k1, · · · ,kr}. Thus there is a proper open set in these positionsand in every other position the open set is the whole space C ([0,T ]) .We need to show that

Γn− (O)≡ {ω : Γ

n (ω)∩O ̸= /0} ∈F .

Now, Γn− (O) = ∩ri=1

{ω : Γn (ω)ki

∩Oki ̸= /0}

, so we consider whether{ω : Γ

n (ω)ki∩Oki ̸= /0

}∈F . (77.2.2)

77.2. SOME FUNDAMENTAL THEOREMS 2599For fixed @ ¢ N and k, the functions {t > fx (uj (-,@)) (t)}, are uniformly boundedand equicontinuous because they are in C*! ({0,T]). Indeed, we have for @ ¢ N,tdMk Iw (6,00) (8,0) S[fe (uy (+50) (1)| = <C(o)|Pr,Vvand fort < t’| fi (uj (+, @)) (t) — fa (uj (-,@)) (¢') |tm ||Me2m I= 1|c(@)|1!() (6,,.4)(s,@)), ds—m [ (im, (0!,,IA(Ont), 4IAveBy Lemma 77.2.5, the set of functions { 2iyc (@) f (uj (-, ©)) fn is pre-compact in X =TC ([0,7]) . We now define a set valued map [” : Q > X byI” (@) = Ujsn { Bye (@)f(u; (-,@))},where the closure is taken in X. Then I” (@) is the closure of a pre-compact set in X andso I” (@) is compact in X. From the definition, a function f is in I (q@) if and only ifd (f, Zc (@)£(w;)) — 0 as 1 + oc, where each w, is one of the u;(-,@) for j >n. In thetopology on X, this happens iff for every k,fi(0) = firm, [| (Gn Five (@) (85 00)), dsloo my twhere the limit is the uniform limit in f.Lemma 77.2.6 The mapping @ >I" (@) is an ¥ measurable set-valued map with valuesin X. If o is a measurable selection, then for each t, @ + 0 (t,@) is ¥ measurable and(t,@) > o(t,@) is B([0,T]) x F measurable.We note that if o is a measurable selection then o (@) € I" (@), soo = 0(-,@) isacontinuous function. To have o measurable would mean that oO; | (open) € -¥, where theopen set is in C ([0,7]).Proof: Let O be a basic open set in X. Then O = [],_; Ox, where O;, is a proper openset of C([0,7]) only for k € {k,,---,k,}. Thus there is a proper open set in these positionsand in every other position the open set is the whole space C ([0,7]) .We need to show thatDl" (0) ={@:I"(@)NOZO} EF.Now, IP" (O) =_, {o I" (@),, OK, A of, so we consider whether{ :T"(@), NOK # of cE. (77.2.2)