2570 CHAPTER 76. IMPLICIT STOCHASTIC EQUATIONS

for a constant C independent of n. Therefore,

limn→∞

E

(∣∣∣∣∣∫ T

0 X[0,τ p](Φn ◦ J−1

)∗Bun ◦ JdW

−∫ T

0 X[0,τ p](Φ◦ J−1

)∗Bu◦ JdW

∣∣∣∣∣)

= 0

Hence

P(An∩ [τ p = ∞])≤ 1ε

E

(∣∣∣∣∣∫ T

0 X[0,τ p](Φn ◦ J−1

)∗Bun ◦ JdW

−∫ T

0 X[0,τ p](Φ◦ J−1

)∗Bu◦ JdW

∣∣∣∣∣)

and solimn→∞

P(An∩ [τ p = ∞]) = 0

Then

P(An) =∞

∑p=1

P(An∩ ([τ p = ∞]\ [τ p−1 < ∞]))

and so from the dominated convergence theorem,

limn→∞

P(An) =∞

∑p=1

limn→∞

P(An∩ ([τ p = ∞]\ [τ p−1 < ∞])) = ∑p

0 = 0.

There was nothing special about T. The same argument holds for all t and so M (t) men-tioned above has been identified as

∫ t0(Φ◦ J−1

)∗Bu◦ JdW. Then from 76.4.51

limn→∞

E

(sup

t∈[0,T ]

∣∣∣∣∫ t

0

(Φ◦ J−1)∗Bu◦ JdW −

∫ t

0

(Φn ◦ J−1)∗Bun ◦ JdW

∣∣∣∣)

= 0

It follows from the usual Borel Cantelli argument that there is a set of measure zero and afurther subsequence such that off this set, all the above convergences happen and also∫ t

0

(Φn ◦ J−1)∗Bun ◦ JdW →

∫ t

0

(Φ◦ J−1)∗Bu◦ JdW

uniformly on [0,T ].The rest of the argument is identical. This yields the following theorem.

Theorem 76.4.9 Suppose V ≡ Lp ([0,T ]×Ω,V ) where p ≥ 2,with the σ algebra of pro-gressively measurable sets and Vω = Lp ([0,T ] ,V ).

Φ ∈ L2([0,T ]×Ω,L2

(Q1/2U,W

)),

f ∈ V ′ ≡ Lp′ ([0,T ]×Ω,V ′)

and both are progressively measurable. Suppose that

λB+A(ω) : Vω → V ′ω , λB+A : V → V ′

2570 CHAPTER 76. IMPLICIT STOCHASTIC EQUATIONSfor a constant C independent of n. Therefore,Ll Ab Fine (v9) Bin oddtin ( ~ [q. Zp.2,] (Pod7!)" BuoJaw ~°HenceP(AnN [tp =) < 1, ( So 7 ty (@poJ')" Bun odd ). ~ Jo 20.2] (PoJ~')" BuoJdWand sojim P (An [tp =~]) =0Then= YP AN ([tp =~] \[Tp-1 < &]))Dpand so from the dominated convergence theorem,lim P(A =¥) lim P(Ay 1 ([tp = ©] \ [tp-1 < ~])) = 0 = 0.n—ooPThere was nothing special about T. The same argument holds for all t and so M (t) men-tioned above has been identified as {j (@oJ~!)* Buo JdW. Then from 76.4.51lim E ( supne \ te(0,T][ (oJ) Buosaw — | (8.011) Baas) =00 0It follows from the usual Borel Cantelli argument that there is a set of measure zero and afurther subsequence such that off this set, all the above convergences happen and also[ (®,0J-1)" Buy osaw > [ (oJ!) * BuoJdW0 0uniformly on [0,7].The rest of the argument is identical. This yields the following theorem.Theorem 76.4.9 Suppose V = L? ((0,T] x Q,V) where p > 2,with the o algebra of pro-gressively measurable sets and Va = L? ([0,T],V).be P (0.71 x Q,D (o'u.w)) ,f € VSL? (0,7) x2,V’)and both are progressively measurable. Suppose thatAB+A(O): Von 3 Vi, AB+A:V > V'