A.5. THE SUBDIVISION OPERATION 471

it follows that one knows also a unique affine simplex φ having φ (vi) =wi defined by

φ (t0, · · · , tp)≡p

∑k=0

tkφ (vk)≡p

∑k=0

tkwk

whenever ∑k tk = 1, tk ≥ 0. As to ∂iφ (t0, · · · , tp−1) , it follows that ∂iφ (σ p−1) equals

[w0, · · · ,0,wi+1, · · · ,wp]

which consists of ordered convex combinations of the vertices of [w0, · · · ,wp] with the wireplaced with 0.

Lemma A.5.9 Let φ be given in the above definition on σ p with values in a convex set Cwhich contains

{w0, · · · ,wp

}. Then φ is an affine map.

Proof: Let ∑mj=1 s j = 1,s j ≥ 0 and consider points of σ p ∑

pi=0 t j

i vi = u j. I need toverify that φ

(∑ j s ju j

)= ∑ j s jφ (u j) . However,

φ

(∑

js ju j

)= φ

(∑

js j

p

∑i=0

t ji vi

)= φ

(p

∑i=0

(∑

js jt

ji

)vi

)

=p

∑i=0

(∑

js jt

ji

)φ (vi) =

p

∑i=0

(∑

js jt

ji

)wi

because ∑pi=0

(∑ j s jt

ji

)= ∑ j s j ∑

pi=0 t j

i = 1. Also

∑j

s jφ (u j) = ∑j

s jφ

(p

∑i=0

t ji vi

)≡∑

js j

p

∑i=0

t ji φ (vi) =

p

∑i=0

(∑

js jt

ji

)wi ■

Definition A.5.10 Denote by Ap (C) the affine singular simplices mapping σ p to C.

Observation A.5.11 Because of these observations, we can regard T̂ in Lemma A.5.6 as ahomomorphism mapping An (C) to An+1 (C). We can also regard Ŝ as a homomorphism onAn (C) which subdivides an affine singular simplex φ into affine singular simplices havingsmaller image and in terms of An (C) we can replace ∂̂ with the standard boundary operator∂ in Lemma A.5.6. It amounts to nothing more than replacing each geometric simplexwith a singular affine simplex, a mapping which has as its image the geometric simplexpreserving order of vertices obtained by the subdivision operation.

Definition A.5.12 Define for f affine, f# : An (C)→ An(C̃)

as the extension of what wasjust described to all of An (C).

Lemma A.5.13 Let f , C, C̃ be as in Definition A.5.12. Then ∂̂ f# = f#∂̂ . Also if b is thebarycenter of [v0, · · · ,vn] , then f (b) is the barycenter of f ([v0, · · · ,vn]) and f# : An (C)→An(C̃). As usual, f# is the homomorphism which acts on chains in An (C) as before.

Proof: Note that the composition of affine maps is affine. It suffices to verify thislemma for a geometric simplex.

∂̂ f# ([v0, · · · ,vn])≡ ∂̂ ([ f (v0) , · · · , f (vn)])≡n

∑k=0

(−1)k[

f (v0) , · · · , f̂ (vk), · · · , f (vn)]

A.5. THE SUBDIVISION OPERATION 471it follows that one knows also a unique affine simplex @ having @ (v;) = w; defined byDp@ (to,°-+ st =) ted (Ve) = Yo ew,k=0whenever Yi; tk = 1, th > 0. As to 0;9 (to,--+ ,tp—1), it follows that 0; (GO p—1) equals[wo,- - 0, Wi1,77° ,W|which consists of ordered convex combinations of the vertices of |wo,--- , Wp] with the w;replaced with 0.Lemma A.5.9 Let be given in the above definition on 0 with values in a convex set Cwhich contains {wo, vee wp} . Then @ is an affine map.Proof: Let vie Sj = 1,s; = 0 and consider points of o, y? ot] vi = uj. I need toverify that @ (Lj 5;wj) =; 5;¢ (uj). However,(5) = bate)- Eb )om Ll)because Y? 9 (Zisit/) =P) syle oti = 1. Also2519 (uj) = Visio (Ze =) ie (vi) = y (Es!) Wij j i=0 j i=0 i=0 \ jDefinition A.5.10 Denote by Ap (C) the affine singular simplices mapping ©, to C.Petllfo)Observation A.5.11 Because of these observations, we can regard T in Lemma A.5.6 as ahomomorphism mapping Ay (C) to An+1 (C). We can also regard S asa homomorphism onAn(C) which subdivides an affine singular simplex @ into affine singular simplices havingsmaller image and in terms of A, (C) we can replace 0 with the standard boundary operator0 in Lemma A.5.6. It amounts to nothing more than replacing each geometric simplexwith a singular affine simplex, a mapping which has as its image the geometric simplexpreserving order of vertices obtained by the subdivision operation.Definition A.5.12 Define for f affine, fy :An(C) > An (C) as the extension of what wasjust described to all of Ay (C).Lemma A.5.13 Let f, C, € be as in Definition A.5.12. Then 0 fy = fx0. Also if b is thebarycenter of |vo,+++ ,Un|, then f (b) is the barycenter of f ([vo,++- ,Un]) and fy: An (C) >An (C). As usual, fx is the homomorphism which acts on chains in A, (C) as before.Proof: Note that the composition of affine maps is affine. It suffices to verify thislemma for a geometric simplex.AO fi ([vo, +> :Un)) =0([f (vo). .f (vn)]) = y (-1)* If (v0) (UK) Lf (vn)