C.1. THE SPINNING TOP AND THE EULER ANGLES 883

picture and the other angles are as shown there as well. We see therefore, that φ′ gives the

angular speed of the line of nodes as the axis, x3 (t) moves around the x3 axis. Thus φ′ is a

measure of the speed the top or gyroscope moves around the fixed x3 axis.

x1

x2

x3

ψ

x3(t)

φ

line of nodes

θ

We will assume our top has the property that I1 = I2. This would happen, for example ifthe density is a constant and if the cross sections perpendicular to the x3 (t) axis are circles.Then the potential energy of the top would be of the form Mgl cosθ where M is the totalmass, g is the acceleration of gravity, and l is the distance along the x3 (t) axis to the centerof mass. Then the Lagrangian is of the form

L =12

I1

[sin2 (θ)

(φ′)2

+(θ′)2]

+12

I3[(

cos2θ)(φ ′)2 +2(cosθ)φ

′ψ′+(ψ ′)2]−Mgl cosθ

and therefore, the equations of motion are(I1 sin2 (θ)φ

′)′+ (I3 cos2 (θ)φ′+ I3 cos(θ)ψ

′)′ = 0 (3.5)(I3 cos(θ)φ

′+ I3ψ′)′ = 0 (3.6)

I1θ′′+(φ′)2 cos(θ)sin(θ)(I3− I1)+ I3 sin(θ)φ

′ψ′−Mgl sin(θ) = 0 (3.7)

The conservation of energy yields

12

I1

[sin2 (θ)

(φ′)2

+(θ′)2]+

I3

2[(cosθ)(φ ′)+ψ

′]2+

C.1. THE SPINNING TOP AND THE EULER ANGLES 883picture and the other angles are as shown there as well. We see therefore, that @’ gives theangular speed of the line of nodes as the axis, x3 (t) moves around the x3 axis. Thus 9’ is ameasure of the speed the top or gyroscope moves around the fixed x3 axis.X3x3(t)X2x]line of nodesWe will assume our top has the property that J, = . This would happen, for example ifthe density is a constant and if the cross sections perpendicular to the x3 (t) axis are circles.Then the potential energy of the top would be of the form Mg/icos@ where M is the totalmass, g is the acceleration of gravity, and / is the distance along the x3 (1) axis to the centerof mass. Then the Lagrangian is of the formL = sl [sin? (8) (0)? + (6")"|45h [(cos @) (@')? +2 (cos 0) ow’ + (w’)?] — Mgl cos 0and therefore, the equations of motion are(I, sin? (6) 6)’ + (Is.cos? (8) 6 + cos (8) y’)’ =0 (3.5)(I;cos (0) 6’ + hy’) =0 (3.6)1,6" + (¢’)’ cos () sin (8) (3 —) +hsin(6) ¢’y'—Mglsin(@)=0 3.7)The conservation of energy yieldshi ‘sin? (8) (6')’ + (6")’| +3 [(cos @) (6") + y']? +