39.2. THE T AND F DISTRIBUTIONS 805

39.2 The T and F DistributionsThese are really interesting. They both involve independent random variables which aredistributed as normal or X 2 distributions. These involve combinations of these otherrandom variables and the idea is to find the density of these combinations. It is a niceapplication of the change of variables theorem.

39.2.1 The T DistributionHere there are two independent random variables, W which is normally distributed withmean 0 and variance 1 and V which is X 2 (r) . Thus, as explained above,

P((V,W ) ∈ A) =∫

A

1√2π

e−w22

1Γ(r/2)2r/2 v(r/2)−1e−v/2dwdv

thus (V,W ) ∈ (0,∞)× (−∞,∞). The idea is to find the probability density of the statistic

T =W√V/r

It is a random variable which has a known distribution. This involves changing the variable.Let

t =w√v/r

,u = v,

(ut

)= r

(vw

)This maps (0,∞)× (−∞,∞) one to one onto (0,∞)× (−∞,∞) as can be seen with a shortcomputation. Let the density function of (t,u) be f (t,u).

P((t,u) ∈U) = P((v,w) ∈ r−1 (U)

)By the change of variables formula for multiple integrals if U is some open set in R2,∫

Uf (t,u)dudt =

∫r−1(U)

1√2π

e−w22

1Γ(r/2)2r/2 v(r/2)−1e−v/2dwdu

=∫r−1(U)

f

(w√v/r

,v

)J (v,w)dwdu

where

J (v,w) =

∣∣∣∣∣∣det

 1 0− 1

2rw

( 1r v)

32

1√1r v

∣∣∣∣∣∣= 1√1r v

Thus

f

(w√v/r

,v

)1√1r v

=1√2π

e−w22

1Γ(r/2)2r/2 v(r/2)−1e−v/2

Then

f

(w√v/r

,v

)=

1√2π

e−w22

1Γ(r/2)2r/2

√1r

vv(r/2)−1e−v/2

39.2. THE T AND F DISTRIBUTIONS 80539.2 The T and F DistributionsThese are really interesting. They both involve independent random variables which aredistributed as normal or 2? distributions. These involve combinations of these otherrandom variables and the idea is to find the density of these combinations. It is a niceapplication of the change of variables theorem.39.2.1 The T DistributionHere there are two independent random variables, W which is normally distributed withmean 0 and variance 1 and V which is 2°? (r). Thus, as explained above,1 _ we 1e von T(r/2) 2" /2P((V,W) €A) = | (2) eY2gdyAthus (V,W) € (0,0) x (—e9, 0). The idea is to find the probability density of the statisticWwJV /rIt is a random variable which has a known distribution. This involves changing the variable.LetThis maps (0,00) x (—90,0°) one to one onto (0,00) x (—s9, 0) as can be seen with a shortcomputation. Let the density function of (t,u) be f (t,u).P((t,u) €U) =P((v,w) Er! (U))By the change of variables formula for multiple integrals if U is some open set in R?,1 1how Von V(r/2)2"7"w— Loot —) J (v,w) dwdu| SS(7/2)-1 6-v/2 wdu| f (t,u) dudtUwhere1 0 IJ(v,w)=|det} 1 w 1 =T(b)F hy rvThusWwW 1 1 w2 1_ - (r/2)-1 ,-v/2Vv e v er( v/r ) 1, Vv2n T(r/2)2"/2Then