134 CHAPTER 5. LINE INTEGRALS AND CURVES

This is called the second mean value theorem for integrals. Hint: Use integration byparts. ∫ b

agd f =−

∫ b

af dg+ f (b)g(b)− f (a)g(a)

Now use the first mean value theorem, the result of Problem 9 to substitute somethingfor∫ b

a f dg and then simplify.

11. Let U be an open subset of Rn and suppose that f : [a,b]×U → R satisfies

(x,y)→ ∂ f∂yi

(x,y) ,(x,y)→ f (x,y)

are all continuous. Show that∫ b

a f (x,y)dx,∫ b

a∂ f∂yi

(x,y)dx all make sense and that

in fact ∂

∂yi

(∫ ba f (x,y)dx

)=∫ b

a∂ f∂yi

(x,y)dx Also explain why y→∫ b

a∂ f∂yi

(x,y)dx iscontinuous. Hint: You will need to use the theorems from one variable calculusabout the existence of the integral for a continuous function. You may also want touse theorems about uniform continuity of continuous functions defined on compactsets.

12. Show∫

0 e−t2dt =

√π

2 . Hint: For x≥ 0, f (x) =(∫ x

0 e−t2dt)2

. Then

f ′ (x) = 2e−x2(∫ x

0e−t2

dt)= 2e−x2

(∫ 1

0e−x2u2

du).

Now integrate by parts to get

f (x) =−e−t2(∫ 1

0e−u2t2

du)|x0−

∫ x

0e−t2

∫ 1

02u2te−u2t2

dudt

Now interchange the order of integration using Problem 6. Then do the integrationsand let x→ ∞.

13. For x > 0,Γ(x)≡∫

0 e−ttx−1dt ≡ limR→∞

∫ R1/R e−ttx−1dt. Show this limit exists. x→

Γ(x) is the gamma function. Also show that Γ(x+1) = xΓ(x) , Γ(1) = 1. How doesΓ(n) for n a positive integer compare with (n−1)!?

14. Suppose Γ is a simple curve and Γ̂ is a simple closed curve. Does there exist a oneto one continuous function g which maps Γ onto Γ̂? Explain why or why not.

15. Suppose Γ is a simple closed curve. Show there exists a continuous function f : Γ→Γ such that for all x ∈ Γ, f(x) ̸= x. However, if Γ is a simple curve, show that iff : Γ→ Γ is continuous, then there is some x ∈ Γ such that f(x) = x. Hint: For thislast part, show first that if h : [0,1]→ [0,1] is continuous, then h(x) = x for somex ∈ [0,1].

16. These two problems are on elementary calculus. Recall ln(n) ≡∫ n

1 (1/t)dt. Showthat for n ∈ N,

12(ln(n+1)+ ln(n))≤

∫ n+1

nln(t)dt ≤ ln(n+1/2)

13411.12.13.14.15.16.CHAPTER 5. LINE INTEGRALS AND CURVESThis is called the second mean value theorem for integrals. Hint: Use integration byparts.b b| gdf = -| fdg+f(b)g(b)—f(a)g (a)Now use the first mean value theorem, the result of Problem 9 to substitute somethingfor f iM fdg and then simplify.Let U be an open subset of R” and suppose that f : [a,b] x U — R satisfies(x,y) > a (x,y), (x,y) + f(%y)b Ofa Oy;. ‘b af . ‘b af .in fact x (2 £9) dx) = i? 5 (x,y) dx Also explain why y > [? 5 (x,y) dx isaare all continuous. Show that i? S (x, y)dx, f (x,y) dx all make sense and thatcontinuous. Hint: You will need to use the theorems from one variable calculusabout the existence of the integral for a continuous function. You may also want touse theorems about uniform continuity of continuous functions defined on compactsets.2Show fe" dt = %. Hint: For x > 0, f (x) = (. * edt) _ Thenf(xy= 2e* (['e*a) =e (j eau) .Now integrate by parts to get1 x 1f(Qa)= et (/ eau) 6-f et Quw2te"" dudt0 0 0Now interchange the order of integration using Problem 6. Then do the integrationsand let x — 9,For x > 0, (x) = fo er dt = limp 4.0 Sur e't*—'dt. Show this limit exists. x >I (x) is the gamma function. Also show that [(x+ 1) =aI (x), (1) = 1. How doesI'(n) for n a positive integer compare with (n —1)!?Suppose I is a simple curve and I is a simple closed curve. Does there exist a oneto one continuous function g which maps TI onto I’? Explain why or why not.Suppose I" is a simple closed curve. Show there exists a continuous function f: [>T such that for all x € T, f(x) Ax. However, if T is a simple curve, show that iff : I — T is continuous, then there is some x € I such that f(x) = x. Hint: For thislast part, show first that if h : [0,1] — [0,1] is continuous, then h(x) = x for somex € [0,1].These two problems are on elementary calculus. Recall In(n) = f;' (1/t) dt. Showthat forn € N,1n+15 (In(n-+1) +In(n)) < | In (t) dt < In(n+1/2)