616 CHAPTER 31. CURVILINEAR COORDINATES

It follows that for G the matrix whose i jth entry is ei ·e j, G = AAT where the ikth entry ofA is ak

i . Therefore, det(G) = det(A)det(AT)= det(A)2 > 0. It follows from 31.11 that if

H is the matrix whose i jth entry is gi j, then GH = I and so H = G−1 and

det(G)det(G−1)= det

(gi j)det(G) = 1.

Therefore, det(G−1

)> 0 also.

Note that det(AAT

)≥ 0 always, because the eigenvalues are nonegative.

As noted above, we have the following definition.

Definition 31.1.7 The matrix (gi j) = G is called the metric tensor.

31.2 Exercises1. Let e1 = i+j,e2 = i−j,e3 = j+k. Find e1,e2,e3, (gi j) ,

(gi j). If

v = i+2j+k, find vi and v j, the contravariant and covariant components of thevector.

2. Let e1 = 2i+j,e2 = i−2j,e3 = k. Find e1,e2,e3, (gi j) ,(gi j). If

v = 2 i− 2j+k, find vi and v j, the contravariant and covariant components of thevector.

3. Suppose e1,e2,e3 have the property that ei ·e j = 0 whenever i ̸= j. Show the sameis true of the dual basis.

4. Let e1,· · · ,e3 be a basis for Rn and let v = viei = viei,w= w je j = w je

j be twovectors. Show

v ·w = gi jviw j = gi jviw j.

5. Show if {ei}3i=1 is a basis in R3

e1 =e2 ×e3

e2 ×e3 ·e1, e2 =

e1 ×e3

e1 ×e3 ·e2, e3 =

e1 ×e2

e1 ×e2 ·e3.

6. Let {ei}ni=1 be a basis and define

e∗i ≡ei

|ei|, e∗i ≡ ei |ei| .

Show e∗i ·e∗j = δij.

7. If v is a vector, v∗i and v∗i, are defined by

v ≡ v∗i e∗i ≡ v∗ie∗i .

These are called the physical components of v. Show

v∗i =vi

|ei|, v∗i = vi |ei| ( No summation on i ).

616CHAPTER 31. CURVILINEAR COORDINATESIt follows that for G the matrix whose ij’” entry is e;-e pG= AA! where the ik‘” entry ofA is ak. Therefore, det (G) = det (A) det (A7) = det (A)* > 0. It follows from 31.11 that ifH is the matrix whose ij’ entry is g'/, then GH =] and so H = G~! anddet (G) det (G~') = det (g’/) det(G) = 1.Therefore, det (G"') >Oalso. §Note that det (AA’) > 0 always, because the eigenvalues are nonegative.As noted above, we have the following definition.Definition 31.1.7 The matrix (g; j) = Gis called the metric tensor.31.2 Exercises1.Let e) =1+j,e, =t—j,e3 =j +k. Find e!,e*,e, (gi), (g'/) Ifv=1+2j +k, find v' and v;, the contravariant and covariant components of thevector.. Let e! = 2i+j,e? =i—2j,e° =k. Find e),e9, 3, (gif); (g'/) Ifv = 2i—2j +k, find v! and v 'j, the contravariant and covariant components of thevector.Suppose €,€2,€3 have the property that e; -e; = 0 whenever i 4 j. Show the sameis true of the dual basis.Let e),:--,e3 be a basis for R” and let v = v'e; = vje',w = wile; = wjel be twovectors. Showvw = gijvw! = g Vjwj;.Show if {e;}7_, is a basis in R°1 e€2 X €3 2 e€, X €&3 3 e; xe2= e = e = .e€ X €3°e]” e€; X€3-€0" e€, X €2:e3Let {e;};_, be a basis and definee; . .* U *D7 =—, ev =e'le;|lei|Show e*-e = 5j.If v is a vector, v; and v*", are defined byv=evie"=v"e;.vThese are called the physical components of v. Showvi = —, v*! =v! le;| (No summation on i).