30.3. STOKE’S THEOREM FROM GREEN’S THEOREM 599

Recall the following definition of the curl of a vector field. Why do we even considerit?

Definition 30.3.1 Let F (x,y,z) = (F1 (x,y,z) ,F2 (x,y,z) ,F3 (x,y,z)) be a C1 vectorfield defined on an open set V in R3. Then

∇×F ≡

∣∣∣∣∣∣i j k∂

∂x∂

∂y∂

∂ zF1 F2 F3

∣∣∣∣∣∣≡(

∂F3

∂y− ∂F2

∂ z

)i+

(∂F1

∂ z− ∂F3

∂x

)j+

(∂F2

∂x− ∂F1

∂y

)k.

This is also called curl(F ) and written as indicated, ∇×F .

The following lemma gives the fundamental identity which will be used in the proof ofStoke’s theorem.

Lemma 30.3.2 Let R : U →V ⊆R3 where U is an open subset of R2 and V is an opensubset of R3. Suppose R is C2 and let F be a C1 vector field defined in V .

(Ru ×Rv) · (∇×F )(R(u,v)) = ((F ◦R)u ·Rv − (F ◦R)v ·Ru)(u,v) . (30.1)

Proof: Start with the left side and let xi = Ri (u,v) for short.

(Ru ×Rv) · (∇×F )(R(u,v)) = ε i jkx juxkvε irs∂Fs

∂xr= (δ jrδ ks −δ jsδ kr)x juxkv

∂Fs

∂xr

= x juxkv∂Fk

∂x j− x juxkv

∂Fj

∂xk=Rv ·

∂ (F ◦R)

∂u−Ru ·

∂ (F ◦R)

∂v

which proves 30.1.The proof of Stoke’s theorem given next follows [10]. First, it is convenient to give a

definition.

Definition 30.3.3 A vector valued function R : U ⊆ Rm → Rn is said to be inCk(U ,Rn

)if it is the restriction to U of a vector valued function which is defined on Rm

and is Ck. That is, this function has continuous partial derivatives up to order k.

Theorem 30.3.4 (Stoke’s Theorem) Let U be any region in R2 for which the con-clusion of Green’s theorem holds and let R∈C2

(U ,R3

)be a one to one function satisfying

|(Ru ×Rv)(u,v)| ̸= 0 for all (u,v) ∈U and let S denote the surface

S ≡ {R(u,v) : (u,v) ∈U} , ∂S ≡ {R(u,v) : (u,v) ∈ ∂U}

where the orientation on ∂S is consistent with the counter clockwise orientation on ∂U (Uis on the left as you walk around ∂U). Then for F a C1 vector field defined near S,∫

∂SF ·dR=

∫S

curl(F ) ·ndS

where n is the normal to S defined by

n≡ Ru ×Rv

|Ru ×Rv|.

30.3. STOKE’S THEOREM FROM GREEN’S THEOREM 599Recall the following definition of the curl of a vector field. Why do we even considerit?Definition 30.3.1 Le: F (x,y,z) = (Fi (x,y,z), (x,y,z), (x,y,z) be aC! vectorfield defined on an open set V in R>. Theni jekOF; OF OF, OF OF, OF=|2 2 a2/.(@% ef), (eM of). (eh OFVx F= ox oy az =($ 3 it (F a) a+ (5 ot) i,hi mh KBThis is also called curl (F’) and written as indicated, V x F.The following lemma gives the fundamental identity which will be used in the proof ofStoke’s theorem.Lemma 30.3.2 Let R: U — V CR? where U is an open subset of R? and V is an opensubset of R?. Suppose R is C* and let F be aC! vector field defined in V.(R, x R,)-(V x F)(R(u,v)) =((FoR),-R,—-(FoR),-R,) (uv). 30.1)Proof: Start with the left side and let x; = R; (u,v) for short.OF, OF,(Ry x R,) : (V x F) (R (u,v)) = Eijk juke Eis — (6 jr dks _— 5 jsSir) Xjurin a_ OF OF) 1, 0(FoR) d(FoR)~ Hite Be tle Gg Be a Rewhich proves 30.1. IfThe proof of Stoke’s theorem given next follows [10]. First, it is convenient to give adefinition.Definition 30.3.3 A vector valued function R.:U CR” > R" is said to be inck (U, R") if it is the restriction to U of a vector valued function which is defined on R™and is C*. That is, this function has continuous partial derivatives up to order k.Theorem 30.3.4 (Stoke’s Theorem) Let U be any region in R? for which the con-clusion of Green’s theorem holds and let R.€ C? (U, R?) be aone to one function satisfying|(R, x R,) (u,v)| 40 for all (u,v) € U and let S denote the surfaceS={R(u,v): (u,v) €U}, ODS={R(u,v) : (u,v) € dU}where the orientation on OS is consistent with the counter clockwise orientation on OU (Uis on the left as you walk around OU). Then for F aC! vector field defined near S,F-dR= [ curl(F)-ndsas swhere n is the normal to S defined byR, x R,n ————__..|R, x R,|