342 APPENDIX B. CURVILINEAR COORDINATES

It follows that for G the matrix whose i jth entry is ei ·e j, G = AAT where the ikth entry ofA is ak

i . Therefore, det(G) = det(A)det(AT)= det(A)2 > 0. It follows from 2.11 that if H

is the matrix whose i jth entry is gi j, then GH = I and so H = G−1 and

det(G)det(G−1)= det

(gi j)det(G) = 1.

Therefore, det(G−1

)> 0 also. ■

Note that det(AAT

)≥ 0 always, because the eigenvalues are nonegative.

As noted above, we have the following definition.

Definition B.1.7 The matrix (gi j) = G is called the metric tensor.

B.2 Exercises1. Let e1 = i+j,e2 = i−j,e3 = j+k. Find e1,e2,e3, (gi j) ,

(gi j). If

v = i+2j+k, find vi and v j, the contravariant and covariant components of thevector.

2. Let e1 = 2i+j,e2 = i−2j,e3 = k. Find e1,e2,e3, (gi j) ,(gi j). If

v = 2 i− 2j+k, find vi and v j, the contravariant and covariant components of thevector.

3. Suppose e1,e2,e3 have the property that ei ·e j = 0 whenever i ̸= j. Show the sameis true of the dual basis.

4. Let e1,· · · ,e3 be a basis for Rn and let v = viei = viei,w= w je j = w je

j be twovectors. Show

v ·w = gi jviw j = gi jviw j.

5. Show if {ei}3i=1 is a basis in R3

e1 =e2×e3

e2×e3 ·e1, e2 =

e1×e3

e1×e3 ·e2, e3 =

e1×e2

e1×e2 ·e3.

6. Let {ei}ni=1 be a basis and define

e∗i ≡ei

|ei|, e∗i ≡ ei |ei| .

Show e∗i ·e∗j = δij.

7. If v is a vector, v∗i and v∗i, are defined by

v ≡ v∗i e∗i ≡ v∗ie∗i .

These are called the physical components of v. Show

v∗i =vi

|ei|, v∗i = vi |ei| ( No summation on i ).

342APPENDIX B. CURVILINEAR COORDINATESIt follows that for G the matrix whose ij’” entry is e;-e pG= AA! where the ik‘” entry ofA is ak. Therefore, det (G) = det (A) det (A’) = det (A)* > 0. It follows from 2.11 that if His the matrix whose ij” entry is g’/, then GH =] and so H = G~! anddet (G) det (G~') = det (g’’) det (G) = 1.Therefore, det (G"!) > Oalso. HfNote that det (AA’) > 0 always, because the eigenvalues are nonegative.As noted above, we have the following definition.Definition B.1.7 The matrix (g; j) = Gis called the metric tensor.B.2 Exercises1.Let e) =1+j,e, =t—j,e3 =j +k. Find e!,e*,e, (gi), (g'/) Ifv=1+2j +k, find v' and v;, the contravariant and covariant components of thevector.Let e! = 21+ j,e* =i-2j7,e =k. Find e}, 0, e3, (gif); (g'/) Ifv = 2i—23-+k, find v’ and v;, the contravariant and covariant components of thevector.Suppose e;,€2,€3 have the property that e;-e; = 0 whenever i 4 j. Show the sameis true of the dual basis.Let e),:--,e3 be a basis for R” and let v = v'e; = vje',w = wile; = wjel be twovectors. Showv-w = gijvw! = g Vjwj;.Show if {e;}7_, is a basis in R°1 e2 X €3 = e€, X €&3 e- e; xe2e€ X €3°e]” e€; X€3-€0" e€, X €2:e3Let {e;};_, be a basis and define*ejShow e*-e = 5j.If v is a vector, v; and v*", are defined byv=evie"=v"e;.vThese are called the physical components of v. Showvi = —, v*! =v! le;| (No summation on i).